Java - Variable Arguments

Table of Contents

Using varargs as a parameter for a method definition, it is possible to pass either an array or a sequence of arguments. If a sequence of arguments are passed, they are converted into an array automatically.

This example shows both an array and a sequence of arguments being passed into the printVarArgArray() method, and how they are treated identically in the code inside the method:

public class VarArgs {       
	// this method will print the entire contents of the parameter passed in       
	void printVarArgArray(int... x) {        
		for (int i = 0; i < x.length; i++) {            
			System.out.print(x[i] + ",");        
	public static void main(String args[]) {       
		VarArgs obj = new VarArgs();              
		//Using an array:       
		int[] testArray = new int[]{10, 20};   
		System.out.println(" ");           
		//Using a sequence of arguments    
		obj.printVarArgArray(5, 6, 5, 8, 6, 31);  

If you define the method like this, it will give compile-time errors.

void method(String... a, int... b , int c){} 
// Compile time error (multiple varargs )

void method(int... a, String b){} 
// Compile time error (varargs must be the last argument 


  • Exercise 1:
    • Create a method with two varargs: int and String.